LeetCode: Maximum Size Subarray Sum Equals k

LeetCode: Maximum Size Subarray Sum Equals k

Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn’t one, return 0 instead.

Note:

The sum of the entire nums array is guaranteed to fit within the 32-bit signed integer range.

Example 1:

Given nums = [1, -1, 5, -2, 3], k = 3, return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the longest)

Example 2:

Given nums = [-2, -1, 2, 1], k = 1, return 2. (because the subarray [-1, 2] sums to 1 and is the longest)

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
public class Solution {
public int maxSubArrayLen(int[] nums, int k) {
if (nums == null || nums.length == 0) {
return 0;
}

int size = nums.length;
Map<Integer, Integer> map = new HashMap<>();

int sum = 0;
int max = 0;
for (int i = 0; i < size; i++) {
int n = nums[i];
sum += n;
if (sum == k) {
max = Math.max(max, i+1);
}
if (!map.containsKey(sum)) {
map.put(sum, i);
}

int remain =sum-k;
if (map.containsKey(remain)) {
max = Math.max(max, i - map.get(remain));
}
}
return max;
}
}