Given a pattern
and a string str
, find if str
follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.
Examples:
- pattern =
"abba"
, str = "dog cat cat dog"
should return true.
- pattern =
"abba"
, str = "dog cat cat fish"
should return false.
- pattern =
"aaaa"
, str = "dog cat cat dog"
should return false.
- pattern =
"abba"
, str = "dog dog dog dog"
should return false.Notes:
You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
| public class Solution { public boolean wordPattern(String pattern, String str) { if (pattern == null || str == null || pattern.isEmpty() || str.isEmpty()) { return false; }
String[] array = str.split(" "); if (pattern.length() != array.length) { return false; }
Map<Character, String> m1 = new HashMap<>(); Map<String, Character> m2 = new HashMap<>();
for (int i = 0; i < pattern.length(); i++) { char c = pattern.charAt(i); String s = array[i]; if (!m1.containsKey(c) && !m2.containsKey(s)) { m1.put(c, s); m2.put(s, c); } else { if(m1.get(c) == null||!m1.get(c).equals(s) || m2.get(s) == null ||m2.get(s) != c){ return false; } } } return true; } }
|